Which of the following carboxylic acids could | vedclass

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Question

(C) Only chiral compounds can be resolved into their enantiomers using an enantiomerically pure chiral resolving agent. $(A)$ $1,5-$dinitro-naphthalen

Vedclass · Accepted Answer

$6$,$6$'-dinitro-biphenyl-$2$,$2$'-dicarboxylic acid

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(C) Only chiral compounds can be resolved into their enantiomers using an enantiomerically pure chiral resolving agent. $(A)$ $1,5-$dinitro-naphthalene$-2,6-$dicarboxylic acid is achiral due to the presence of a plane of symmetry. $(B)$ $2,5-$dinitro-terephthalic acid is achiral due to the presence of a plane of symmetry. $(C)$ $6$,$6$'-dinitro-biphenyl-$2$,$2$'-dicarboxylic acid exhibits atropisomerism due to restricted rotation around the single bond connecting the two phenyl rings,caused by the bulky ortho-substituents. This makes the molecule chiral and resolvable. $(D)$ $8-$nitro-anthracene$-1-$carboxylic acid is planar and achiral. Therefore,the correct option is $(C)$.

Which of the following carboxylic acids could be resolved by reaction with an enantiomerically pure chiral amine?

Similar Questions

The above conversion can be done by:

The increasing order of the acidity of the following carboxylic acids is:

In the reaction sequence,$[X]$ is a ketone:
$[X] \xrightarrow{KMnO_4/OH^{-}/\Delta} HOOC-(CH_2)_3-CH(CH_3)-COOH$
$[X]$ will be:

$\text{CH}_3\text{COOH} \xrightarrow{\text{LiAlH}_4} \text{X} \xrightarrow{\text{PCl}_5} \text{Y} \xrightarrow{\text{Alcoholic KOH}} \text{Z}$. Find product '$Z$' in the above reaction.

Which of the following is the correct order of decarboxylation of $\beta$-keto carboxylate anion?

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